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Drawing lines: LOIN (Part 6 of 7)

[Commodore 64 version]

Name: LOIN (Part 6 of 7) [Show more] Type: Subroutine Category: Drawing lines Summary: Draw a steep line going up and left or down and right Deep dive: Bresenham's line algorithm
Context: See this subroutine in context in the source code References: No direct references to this subroutine in this source file

This routine draws a line from (X1, Y1) to (X2, Y2). It has multiple stages. If we get here, then: * The line is going up and left (no swap) or down and right (swap) * X1 < X2 and Y1 >= Y2 * Draw from (X1, Y1) at top left to (X2, Y2) at bottom right, omitting the first pixel
CLC ; Clear the C flag LDA SWAP ; If SWAP = 0 then we didn't swap the coordinates above, BEQ LI17 ; so jump down to LI17 to skip plotting the first pixel DEX ; Decrement the counter in X because we're about to plot ; the first pixel .LIL5 ; We now loop along the line from left to right, using X ; as a decreasing counter, and at each count we plot a ; single pixel using the pixel mask in R2 LDA R2 ; Fetch the pixel byte from R2 EOR (SC),Y ; Store R into screen memory at SC(1 0), using EOR STA (SC),Y ; logic so it merges with whatever is already on-screen .LI17 DEY ; Decrement Y to step up along the y-axis BPL LI16 ; If Y is positive we are still within the same ; character block, so skip to LI16 ; We now need to move up into the character block above, ; and each character row in screen memory takes up $140 ; bytes ($100 for the visible part and $20 for each of ; the blank borders on the side of the screen), so ; that's what we need to subtract from SC(1 0) ; ; We also know the C flag is clear, as we cleared it ; above, so we can subtract $13F in order to get the ; correct result LDA SC ; Set SC(1 0) = SC(1 0) - $140 SBC #$3F ; STA SC ; Starting with the low bytes LDA SCH ; And then subtracting the high bytes SBC #$01 STA SCH LDY #7 ; Set the pixel line to the last line in that character ; block .LI16 LDA S2 ; Set S2 = S2 + P2 to update the slope error ADC P2 STA S2 BCC LIC5 ; If the addition didn't overflow, jump to LIC5 LSR R2 ; Otherwise we just overflowed, so shift the single ; pixel in R2 to the right, so the next pixel we plot ; will be at the next x-coordinate along BCC LIC5 ; If the pixel didn't fall out of the right end of R ; into the C flag, then jump to LIC5 ROR R2 ; Otherwise we need to move over to the next character ; block, so first rotate R right so the set C flag goes ; back into the left end, giving %10000000 LDA SC ; Add 8 to SC, so SC(1 0) now points to the next ADC #8 ; character along to the right STA SC BCC LIC5 ; If the addition of the low bytes of SC overflowed, INC SC+1 ; increment the high byte CLC ; Clear the C flag .LIC5 DEX ; Decrement the counter in X BNE LIL5 ; If we haven't yet reached the right end of the line, ; loop back to LIL5 to plot the next pixel along LDY YSAV ; Restore Y from YSAV, so that it's preserved RTS ; Return from the subroutine